What is the answer to log_{3}(x)+log_{9}(3x)=-1 ?

The answer to log_{3}(x)+log_{9}(3x)=-1 is x= 1/3

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log_{3}(x)+log_{9}(3x)=-1

lo g_{3} (x) + lo g_{9} (3 x) = - 1

x = \frac{1}{3}

Decimal Notation

x = 0.33333 \dots

Solution steps

lo g_{3} (x) + lo g_{9} (3 x) = - 1

Apply log rules

x = \frac{1}{3}

Verify Solutions:

x = \frac{1}{3}

True

The solution is

x = \frac{1}{3}

lo g_{10} (x) (4) = - \frac{1}{2}

x, lo g_{10} (x) = y + 4

lo g_{4} (3 x) + 2 lo g_{4} (6) = 4

lo g_{2} (x + 3) + lo g_{2} (x - 3) = 0

b, ln (2 b) = 4 ln (4 b)

What is the answer to log_{3}(x)+log_{9}(3x)=-1 ?
The answer to log_{3}(x)+log_{9}(3x)=-1 is x= 1/3
Solve for x: log_{3}(x)+log_{9}(3x)=-1
The solution is x= 1/3