What is the answer to 2log_{x}(3 3/8)=6 ?

The answer to 2log_{x}(3 3/8)=6 is x=e^{(ln(27/8))/3}

Solve for x: 2log_{x}(3 3/8)=6

The solution is x=e^{(ln(27/8))/3}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 lo g_{x} (3 \frac{3}{8}) = 6

x = e^{\frac{l n ( \frac{27}{8} )}{3}}

Decimal Notation

x = 1.5

Solution steps

2 lo g_{x} (3 \frac{3}{8}) = 6

Convert mixed numbers to improper fractions:

3 \frac{3}{8} = \frac{27}{8}

2 lo g_{x} (\frac{27}{8}) = 6

Divide both sides by

2

lo g_{x} (\frac{27}{8}) = 3

Apply log rules

\frac{ln ( \frac{27}{8} )}{ln ( x )} = 3

Multiply both sides by

ln (x)

\frac{ln ( \frac{27}{8} )}{ln ( x )} ln (x) = 3 ln (x)

Simplify

ln (\frac{27}{8}) = 3 ln (x)

Switch sides

3 ln (x) = ln (\frac{27}{8})

Divide both sides by

3

ln (x) = \frac{ln ( \frac{27}{8} )}{3}

Apply log rules

x = e^{\frac{l n ( \frac{27}{8} )}{3}}

Verify Solutions:

x = e^{\frac{l n ( \frac{27}{8} )}{3}}

True

The solution is

x = e^{\frac{l n ( \frac{27}{8} )}{3}}

lo g_{2} (x - 1) = 4 - lo g_{2} (x + 1)

lo g_{6} (3 x^{2} - 3 x) = 2

lo g_{10} (x - 3) 9 = 2

lo g_{3} (6 x) + lo g_{3} (2) = 3

x, ln (y) = - 3 ln (x) + c

What is the answer to 2log_{x}(3 3/8)=6 ?
The answer to 2log_{x}(3 3/8)=6 is x=e^{(ln(27/8))/3}
Solve for x: 2log_{x}(3 3/8)=6
The solution is x=e^{(ln(27/8))/3}