What is the answer to 20log_{10}(1+x)=0.1 ?

The answer to 20log_{10}(1+x)=0.1 is x=10^{0.005}-1

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20log_{10}(1+x)=0.1

20 lo g_{10} (1 + x) = 0.1

x = 1 0^{0.005} - 1

Decimal Notation

x = 0.01157 \dots

Solution steps

20 lo g_{10} (1 + x) = 0.1

Divide both sides by

20

lo g_{10} (1 + x) = 0.005

Apply log rules

1 + x = 1 0^{0.005}

Solve

1 + x = 1 0^{0.005} : x = 1 0^{0.005} - 1

x = 1 0^{0.005} - 1

Verify Solutions:

x = 1 0^{0.005} - 1

True

The solution is

x = 1 0^{0.005} - 1

20 + ln (5) = 2 ln (x)

lo g_{8} (lo g_{5} (x)) = 0

0 = 80 - 10 lo g_{2} (t + 1)

lo g_{x} (\frac{1}{125}) = - 9

lo g_{10} (x + 3) = 0

What is the answer to 20log_{10}(1+x)=0.1 ?
The answer to 20log_{10}(1+x)=0.1 is x=10^{0.005}-1
Solve for x: 20log_{10}(1+x)=0.1
The solution is x=10^{0.005}-1