What is the answer to log_{1/2}(5(x-1))=3 ?

The answer to log_{1/2}(5(x-1))=3 is x= 41/40

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log_{1/2}(5(x-1))=3

lo g_{\frac{1}{2}} (5 (x - 1)) = 3

x = \frac{41}{40}

Solution steps

lo g_{\frac{1}{2}} (5 (x - 1)) = 3

Apply log rules

5 (x - 1) = \frac{1}{8}

Solve

5 (x - 1) = \frac{1}{8} : x = \frac{41}{40}

x = \frac{41}{40}

lo g_{2} (x) - lo g_{2} (x + 1) = 2

lo g_{2} (x + 5) = 2 + lo g_{2} (x + 8)

2 lo g_{3} (x) = 2 + lo g_{3} (x - 2)

ln (4 + a e^{b t}) = 0

ln (x + 5) = ln (x - 1) + ln (x + 1)

What is the answer to log_{1/2}(5(x-1))=3 ?
The answer to log_{1/2}(5(x-1))=3 is x= 41/40
Solve for x: log_{1/2}(5(x-1))=3
The solution is x= 41/40