What is the answer to solvefor x,y=sqrt(ln(x)) ?

The answer to solvefor x,y=sqrt(ln(x)) is x=e^{y^2} {y>= 0}

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solvefor x,y=sqrt(ln(x))

solve for

x, y = ln (x)

x = e^{y^{2}} {y \geq 0}

Solution steps

y = ln (x)

Rewrite the equation with

ln (x) = u

y = u

Solve

y = u : u = y^{2} {y \geq 0}

u = y^{2} {y \geq 0}

Substitute back

u = ln (x),

solve for

x

Solve

ln (x) = y^{2} : x = e^{y^{2}}

x = e^{y^{2}}

Verify Solutions:

x = e^{y^{2}} {y \geq 0}

The solution is

x = e^{y^{2}} {y \geq 0}

3 lo g_{e} (x + 1) = - lo g_{e} (2 x - 1)

ln (x - 1) + ln (3) = 2

4 = \frac{ln ( 4 x )}{ln ( 2 x )}

2 lo g_{2} (x) = x

lo g_{10} (3 + x) = lo g_{10} (x) + 2

What is the answer to solvefor x,y=sqrt(ln(x)) ?
The answer to solvefor x,y=sqrt(ln(x)) is x=e^{y^2} {y>= 0}