What is the answer to ln(x-1)+ln(3)=2 ?

The answer to ln(x-1)+ln(3)=2 is x=(e^2)/3+1

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ln(x-1)+ln(3)=2

ln (x - 1) + ln (3) = 2

x = \frac{e ^{2}}{3} + 1

Decimal Notation

x = 3.46301 \dots

Solution steps

ln (x - 1) + ln (3) = 2

Move

ln (3)

to the right side

ln (x - 1) = 2 - ln (3)

Apply log rules

x - 1 = \frac{e ^{2}}{3}

Solve

x - 1 = \frac{e ^{2}}{3} : x = \frac{e ^{2}}{3} + 1

x = \frac{e ^{2}}{3} + 1

Verify Solutions:

x = \frac{e ^{2}}{3} + 1

True

The solution is

x = \frac{e ^{2}}{3} + 1

4 = \frac{ln ( 4 x )}{ln ( 2 x )}

2 lo g_{2} (x) = x

lo g_{10} (3 + x) = lo g_{10} (x) + 2

lo g_{2} (z + 6) = lo g_{2} (z - 1) + 3

0.5075 = - lo g_{10} (x)

What is the answer to ln(x-1)+ln(3)=2 ?
The answer to ln(x-1)+ln(3)=2 is x=(e^2)/3+1
Solve for x: ln(x-1)+ln(3)=2
The solution is x=(e^2)/3+1