What is the answer to log_{10}(2x+1)=-0.5 ?

The answer to log_{10}(2x+1)=-0.5 is x=(1-sqrt(10))/(2sqrt(10))

Solve for x: log_{10}(2x+1)=-0.5

The solution is x=(1-sqrt(10))/(2sqrt(10))

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lo g_{10} (2 x + 1) = - 0.5

x = \frac{1 - 10}{2 10}

Decimal Notation

x = - 0.34188 \dots

Solution steps

lo g_{10} (2 x + 1) = - 0.5

Apply log rules

2 x + 1 = \frac{1}{10}

Solve

2 x + 1 = \frac{1}{10} : x = \frac{1 - 10}{2 10}

x = \frac{1 - 10}{2 10}

2 + lo g_{10} (1 - x) = 0

3 + lo g_{2} (2 x) = lo g_{2} (17 x - 5)

ln (x - 4) - ln (x) = 5

x, ln (y) = 2 ln (x) + 2 c

lo g_{2 - x} (2 x^{2} - 1) = 2

What is the answer to log_{10}(2x+1)=-0.5 ?
The answer to log_{10}(2x+1)=-0.5 is x=(1-sqrt(10))/(2sqrt(10))
Solve for x: log_{10}(2x+1)=-0.5
The solution is x=(1-sqrt(10))/(2sqrt(10))