What is the answer to log_{3}(4)+log_{3}(x)=1 ?

The answer to log_{3}(4)+log_{3}(x)=1 is x= 3/4

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log_{3}(4)+log_{3}(x)=1

lo g_{3} (4) + lo g_{3} (x) = 1

x = \frac{3}{4}

Solution steps

lo g_{3} (4) + lo g_{3} (x) = 1

Move

lo g_{3} (4)

to the right side

lo g_{3} (x) = 1 - lo g_{3} (4)

Apply log rules

x = \frac{3}{4}

Verify Solutions:

x = \frac{3}{4}

True

The solution is

x = \frac{3}{4}

7.4 = lo g_{10} (x)

y, ln (y) = e^{x} + ln (x)

lo g_{4} (8 x + 1) = 2

lo g_{a} (n^{m}) = 16

(ln (∣ x - 1 ∣ - 1)) = - 1

What is the answer to log_{3}(4)+log_{3}(x)=1 ?
The answer to log_{3}(4)+log_{3}(x)=1 is x= 3/4
Solve for x: log_{3}(4)+log_{3}(x)=1
The solution is x= 3/4