What is the answer to log_{4}(8x+1)=2 ?

The answer to log_{4}(8x+1)=2 is x= 15/8

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log_{4}(8x+1)=2

lo g_{4} (8 x + 1) = 2

x = \frac{15}{8}

Solution steps

lo g_{4} (8 x + 1) = 2

Apply log rules

8 x + 1 = 16

Solve

8 x + 1 = 16 : x = \frac{15}{8}

x = \frac{15}{8}

lo g_{a} (n^{m}) = 16

(ln (∣ x - 1 ∣ - 1)) = - 1

(lo g_{5} (x))^{2} = 1

A (x) = ln (x) - 1

2 = lo g_{10} (3 x)

What is the answer to log_{4}(8x+1)=2 ?
The answer to log_{4}(8x+1)=2 is x= 15/8
Solve for x: log_{4}(8x+1)=2
The solution is x= 15/8