What is the answer to (ln(|x-1|-1))=-1 ?

The answer to (ln(|x-1|-1))=-1 is x=-1/e ,x= 1/e+2

Solve for x: (ln(|x-1|-1))=-1

The solution is x=-1/e ,x= 1/e+2

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(ln (∣ x - 1 ∣ - 1)) = - 1

x = - \frac{1}{e}, x = \frac{1}{e} + 2

Solution steps

(ln (∣ x - 1 ∣ - 1)) = - 1

Apply log rules

∣ x - 1 ∣ - 1 = \frac{1}{e}

Solve

∣ x - 1 ∣ - 1 = \frac{1}{e} : x = - \frac{1}{e} or x = \frac{1}{e} + 2

x = - \frac{1}{e}, x = \frac{1}{e} + 2

(lo g_{5} (x))^{2} = 1

A (x) = ln (x) - 1

2 = lo g_{10} (3 x)

lo g_{4} (lo g_{2} (x + 1)) = 1

x, (f x) = 2 x + ln (x)

What is the answer to (ln(|x-1|-1))=-1 ?
The answer to (ln(|x-1|-1))=-1 is x=-1/e ,x= 1/e+2
Solve for x: (ln(|x-1|-1))=-1
The solution is x=-1/e ,x= 1/e+2