What is the answer to log_{4}(2x^2-4x)=2 ?

The answer to log_{4}(2x^2-4x)=2 is x=4,x=-2

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log_{4}(2x^2-4x)=2

lo g_{4} (2 x^{2} - 4 x) = 2

x = 4, x = - 2

Solution steps

lo g_{4} (2 x^{2} - 4 x) = 2

Apply log rules

2 x^{2} - 4 x = 16

Solve

2 x^{2} - 4 x = 16 : x = 4, x = - 2

x = 4, x = - 2

8.4 = lo g_{10} (x)

- 9.042 = 20 lo g_{10} (x)

lo g_{3} (x^{2} + 4 x) = 4

lo g_{3} (81) = 4 lo g_{3} (x + 1)

ln (1.8) - ln (x) = 0.2742

What is the answer to log_{4}(2x^2-4x)=2 ?
The answer to log_{4}(2x^2-4x)=2 is x=4,x=-2
Solve for x: log_{4}(2x^2-4x)=2
The solution is x=4,x=-2