What is the answer to log_{2}(8x-3)=2+log_{10}(2) ?

The answer to log_{2}(8x-3)=2+log_{10}(2) is x=(2^{2+log_{10}(2)}+3)/8

Solve for x: log_{2}(8x-3)=2+log_{10}(2)

The solution is x=(2^{2+log_{10}(2)}+3)/8

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lo g_{2} (8 x - 3) = 2 + lo g_{10} (2)

x = \frac{2 ^{2 + l o g_{10} (2)} + 3}{8}

Solution steps

lo g_{2} (8 x - 3) = 2 + lo g_{10} (2)

Apply log rules

8 x - 3 = 2^{2 + l o g_{10} (2)}

Solve

8 x - 3 = 2^{2 + l o g_{10} (2)} : x = \frac{2 ^{2 + l o g_{10} (2)} + 3}{8}

x = \frac{2 ^{2 + l o g_{10} (2)} + 3}{8}

lo g_{3} ((x + 10)^{4}) = 4

- 20 lo g_{10} (x) = 10.2

lo g_{2} ((r + 7)^{2}) = 6

2 ln (3 x) + ln (x - 1) = 0

86 = 20 lo g_{10} (\frac{x}{20})

What is the answer to log_{2}(8x-3)=2+log_{10}(2) ?
The answer to log_{2}(8x-3)=2+log_{10}(2) is x=(2^{2+log_{10}(2)}+3)/8
Solve for x: log_{2}(8x-3)=2+log_{10}(2)
The solution is x=(2^{2+log_{10}(2)}+3)/8