What is the answer to -20log_{10}(x)=10.2 ?

The answer to -20log_{10}(x)=10.2 is x= 1/(10^{0.51)}

Solve for x: -20log_{10}(x)=10.2

The solution is x= 1/(10^{0.51)}

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- 20 lo g_{10} (x) = 10.2

x = \frac{1}{1 0 ^{0.51}}

Solution steps

- 20 lo g_{10} (x) = 10.2

Divide both sides by

- 20

lo g_{10} (x) = - 0.51

Apply log rules

x = \frac{1}{1 0 ^{0.51}}

Verify Solutions:

x = \frac{1}{1 0 ^{0.51}}

True

The solution is

x = \frac{1}{1 0 ^{0.51}}

lo g_{2} ((r + 7)^{2}) = 6

2 ln (3 x) + ln (x - 1) = 0

86 = 20 lo g_{10} (\frac{x}{20})

x, t = 5 ln (x)

ln (3 x^{2} - 2 x) = 0

What is the answer to -20log_{10}(x)=10.2 ?
The answer to -20log_{10}(x)=10.2 is x= 1/(10^{0.51)}
Solve for x: -20log_{10}(x)=10.2
The solution is x= 1/(10^{0.51)}