What is the answer to ln(x^2+x)=ln(x^2)+ln(x) ?

The answer to ln(x^2+x)=ln(x^2)+ln(x) is x=(1+sqrt(5))/2

Solve for x: ln(x^2+x)=ln(x^2)+ln(x)

The solution is x=(1+sqrt(5))/2

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ln (x^{2} + x) = ln (x^{2}) + ln (x)

x = \frac{1 + 5}{2}

Solution steps

ln (x^{2} + x) = ln (x^{2}) + ln (x)

Apply log rules

x^{2} + x = x^{3}

Solve

x^{2} + x = x^{3} : x = 0, x = \frac{1 + 5}{2}, x = \frac{1 - 5}{2}

x = 0, x = \frac{1 + 5}{2}, x = \frac{1 - 5}{2}

Verify Solutions:

x = 0

False

, x = \frac{1 + 5}{2}

True

, x = \frac{1 - 5}{2}

False

The solution is

x = \frac{1 + 5}{2}

lo g_{4} (6 x - 7) = 1

y, ln (9 y) = 2 t + 9

ln (r) + ln (10) = \frac{3}{2}

2 ln (x + 1) + 1 = 0

lo g_{3} (8 x - 15) = 4

What is the answer to ln(x^2+x)=ln(x^2)+ln(x) ?
The answer to ln(x^2+x)=ln(x^2)+ln(x) is x=(1+sqrt(5))/2
Solve for x: ln(x^2+x)=ln(x^2)+ln(x)
The solution is x=(1+sqrt(5))/2