What is the answer to ln(x+1)-ln(x+2)=ln(1) ?

The answer to ln(x+1)-ln(x+2)=ln(1) is No Solution for x\in\mathbb{R}

Solve for x: ln(x+1)-ln(x+2)=ln(1)

The solution is No Solution for x\in\mathbb{R}

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ln (x + 1) - ln (x + 2) = ln (1)

No Solution for x \in R

Solution steps

ln (x + 1) - ln (x + 2) = ln (1)

Add

ln (x + 2)

to both sides

ln (x + 1) - ln (x + 2) + ln (x + 2) = ln (1) + ln (x + 2)

Simplify

ln (x + 1) = ln (1) + ln (x + 2)

Apply log rules

x + 1 = x + 2

Solve

x + 1 = x + 2 :

No Solution

No Solution for x \in R

lo g_{10} (z) = 9.3

ln (3 x - 4) = 6

lo g_{2} (x) - 3 lo g_{10} (x) = 2

x, y = lo g_{a} (7 x - b) + 3

95 = 20 lo g_{10} (\frac{275}{x})

What is the answer to ln(x+1)-ln(x+2)=ln(1) ?
The answer to ln(x+1)-ln(x+2)=ln(1) is No Solution for x\in\mathbb{R}
Solve for x: ln(x+1)-ln(x+2)=ln(1)
The solution is No Solution for x\in\mathbb{R}