What is the answer to 50=68-20log_{10}(t+1) ?

The answer to 50=68-20log_{10}(t+1) is t=10^{9/10}-1

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50=68-20log_{10}(t+1)

50 = 68 - 20 lo g_{10} (t + 1)

t = 1 0^{\frac{9}{10}} - 1

Decimal Notation

t = 6.94328 \dots

Solution steps

50 = 68 - 20 lo g_{10} (t + 1)

Switch sides

68 - 20 lo g_{10} (t + 1) = 50

Move

68

to the right side

- 20 lo g_{10} (t + 1) = - 18

Divide both sides by

- 20

lo g_{10} (t + 1) = \frac{9}{10}

Apply log rules

t + 1 = 1 0^{\frac{9}{10}}

Solve

t + 1 = 1 0^{\frac{9}{10}} : t = 1 0^{\frac{9}{10}} - 1

t = 1 0^{\frac{9}{10}} - 1

Verify Solutions:

t = 1 0^{\frac{9}{10}} - 1

True

The solution is

t = 1 0^{\frac{9}{10}} - 1

ln (2 t + 3) = 4

n = - \frac{lo g _{10} ( p )}{10}

\frac{11}{10} = lo g_{2} (x)

x = ln (x + 2)

a, lo g_{b} (2 a) = 4

What is the answer to 50=68-20log_{10}(t+1) ?
The answer to 50=68-20log_{10}(t+1) is t=10^{9/10}-1
Solve for t: 50=68-20log_{10}(t+1)
The solution is t=10^{9/10}-1