What are the solutions to the equation y^2-8y+9=0 ?

The solutions to the equation y^2-8y+9=0 are y=4+sqrt(7),y=4-sqrt(7)

Find the zeros of y^2-8y+9=0

The zeros of y^2-8y+9=0 are y=4+sqrt(7),y=4-sqrt(7)

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y^{2} - 8 y + 9 = 0

y = 4 + 7, y = 4 - 7

Solution steps

y^{2} - 8 y + 9 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 9 = 27

y_{1, 2} = \frac{- ( - 8 ) \pm 2 7}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 8 ) + 2 7}{2 \cdot 1}, y_{2} = \frac{- ( - 8 ) - 2 7}{2 \cdot 1}

y = \frac{- ( - 8 ) + 2 7}{2 \cdot 1} : 4 + 7

y = \frac{- ( - 8 ) - 2 7}{2 \cdot 1} : 4 - 7

The solutions to the quadratic equation are:

y = 4 + 7, y = 4 - 7

9 = - 7 x + 7 x^{2}

2 x < 8

7 x^{2} = 3 x^{2} + 25

0 = 2 x^{2} + 3 x

- 4 (3 x + 2) = - 3 (4 x + 5)

What are the solutions to the equation y^2-8y+9=0 ?
The solutions to the equation y^2-8y+9=0 are y=4+sqrt(7),y=4-sqrt(7)
Find the zeros of y^2-8y+9=0
The zeros of y^2-8y+9=0 are y=4+sqrt(7),y=4-sqrt(7)