What are the solutions to the equation solvefor a,a^2+b^2=c^2 ?

The solutions to the equation solvefor a,a^2+b^2=c^2 are a=sqrt(c^2-b^2),a=-sqrt(c^2-b^2)

Find the zeros of solvefor a,a^2+b^2=c^2

The zeros of solvefor a,a^2+b^2=c^2 are a=sqrt(c^2-b^2),a=-sqrt(c^2-b^2)

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solve for

a, a^{2} + b^{2} = c^{2}

a = c^{2} - b^{2}, a = - c^{2} - b^{2}

Solution steps

a^{2} + b^{2} = c^{2}

Move

b^{2}

to the right side

a^{2} = c^{2} - b^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = c^{2} - b^{2}, a = - c^{2} - b^{2}

2 (x - 5)^{2} - 9 = 0

x^{2} + 1

y, x^{2} = y^{2}

- 2 x^{2} + x = - 6

x^{2} + 2 x + 2

What are the solutions to the equation solvefor a,a^2+b^2=c^2 ?
The solutions to the equation solvefor a,a^2+b^2=c^2 are a=sqrt(c^2-b^2),a=-sqrt(c^2-b^2)
Find the zeros of solvefor a,a^2+b^2=c^2
The zeros of solvefor a,a^2+b^2=c^2 are a=sqrt(c^2-b^2),a=-sqrt(c^2-b^2)