What are the solutions to the equation roots x^2+6x+c ?

The solutions to the equation roots x^2+6x+c are x=-3+sqrt(-c+9),x=-sqrt(-c+9)-3

Find the zeros of roots x^2+6x+c

The zeros of roots x^2+6x+c are x=-3+sqrt(-c+9),x=-sqrt(-c+9)-3

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roots

x^{2} + 6 x + c

x = - 3 + - c + 9, x = - - c + 9 - 3

Solution steps

x^{2} + 6 x + c

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 6 x + c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot c}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot c : 2 9 - c

x_{1, 2} = \frac{- 6 \pm 2 9 - c}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 9 - c}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 9 - c}{2 \cdot 1}

x = \frac{- 6 + 2 9 - c}{2 \cdot 1} : - 3 + - c + 9

x = \frac{- 6 - 2 9 - c}{2 \cdot 1} : - - c + 9 - 3

The solutions to the quadratic equation are:

x = - 3 + - c + 9, x = - - c + 9 - 3

x^{2} - 4 x + 1

3 x^{2} + 11 x = 4

x^{2} + x - 1

- x^{2} - 4 x - 2

(x + 4)^{2} - 38 = - 22

What are the solutions to the equation roots x^2+6x+c ?
The solutions to the equation roots x^2+6x+c are x=-3+sqrt(-c+9),x=-sqrt(-c+9)-3
Find the zeros of roots x^2+6x+c
The zeros of roots x^2+6x+c are x=-3+sqrt(-c+9),x=-sqrt(-c+9)-3