What are the solutions to the equation factor 3x^2+11x=4 ?

The solutions to the equation factor 3x^2+11x=4 are x= 1/3 ,x=-4

Find the zeros of factor 3x^2+11x=4

The zeros of factor 3x^2+11x=4 are x= 1/3 ,x=-4

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3 x^{2} + 11 x = 4

x = \frac{1}{3}, x = - 4

Decimal Notation

x = 0.33333 \dots, x = - 4

Solution steps

3 x^{2} + 11 x = 4

Move

4

to the left side

3 x^{2} + 11 x - 4 = 0

Factor

3 x^{2} + 11 x - 4 : (3 x - 1) (x + 4)

(3 x - 1) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 1 = 0 or x + 4 = 0

Solve

3 x - 1 = 0 : x = \frac{1}{3}

Solve

x + 4 = 0 : x = - 4

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 4

x^{2} + x - 1

- x^{2} - 4 x - 2

(x + 4)^{2} - 38 = - 22

x^{2} + 9 = 3

y, x^{2} - 2 x y + y^{2} = 0

What are the solutions to the equation factor 3x^2+11x=4 ?
The solutions to the equation factor 3x^2+11x=4 are x= 1/3 ,x=-4
Find the zeros of factor 3x^2+11x=4
The zeros of factor 3x^2+11x=4 are x= 1/3 ,x=-4