What are the solutions to the equation 3(x+7)^2-32=-29 ?

The solutions to the equation 3(x+7)^2-32=-29 are x=-6,x=-8

Find the zeros of 3(x+7)^2-32=-29

The zeros of 3(x+7)^2-32=-29 are x=-6,x=-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 (x + 7)^{2} - 32 = - 29

x = - 6, x = - 8

Solution steps

3 (x + 7)^{2} - 32 = - 29

Move

32

to the right side

3 (x + 7)^{2} = 3

Divide both sides by

3

(x + 7)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = 1 : x = - 6

Solve

x + 7 = - 1 : x = - 8

The solutions to the quadratic equation are:

x = - 6, x = - 8

x^{2} + 5 x - 14 = 0

6 b^{2} - 7 b - 21 = - 1

2 (x^{2} - 7) + 3 = - 3

x^{2} + 52 = - 12 x

5 (x^{2} - 4) - 5 = - 5

What are the solutions to the equation 3(x+7)^2-32=-29 ?
The solutions to the equation 3(x+7)^2-32=-29 are x=-6,x=-8
Find the zeros of 3(x+7)^2-32=-29
The zeros of 3(x+7)^2-32=-29 are x=-6,x=-8