What are the solutions to the equation roots s^2-s+4 ?

The solutions to the equation roots s^2-s+4 are s= 1/2+i(sqrt(15))/2 ,s= 1/2-i(sqrt(15))/2

Find the zeros of roots s^2-s+4

The zeros of roots s^2-s+4 are s= 1/2+i(sqrt(15))/2 ,s= 1/2-i(sqrt(15))/2

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roots

s^{2} - s + 4

s = \frac{1}{2} + i \frac{15}{2}, s = \frac{1}{2} - i \frac{15}{2}

Solution steps

s^{2} - s + 4

The roots are the intercepts with the x-axis

(y = 0)

s^{2} - s + 4 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

(- 1)^{2} - 4 \cdot 1 \cdot 4 : 15 i

s_{1, 2} = \frac{- ( - 1 ) \pm 15 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 1 ) + 15 i}{2 \cdot 1}, s_{2} = \frac{- ( - 1 ) - 15 i}{2 \cdot 1}

s = \frac{- ( - 1 ) + 15 i}{2 \cdot 1} : \frac{1}{2} + i \frac{15}{2}

s = \frac{- ( - 1 ) - 15 i}{2 \cdot 1} : \frac{1}{2} - i \frac{15}{2}

The solutions to the quadratic equation are:

s = \frac{1}{2} + i \frac{15}{2}, s = \frac{1}{2} - i \frac{15}{2}

x^{2} - 6 x + 9

25 x^{2} + 40 x - 9 = 0

10 - 2 x^{2} = - 198

y, y = x y + x^{2} + 1

y, x^{2} + x y + y^{2} = 9

What are the solutions to the equation roots s^2-s+4 ?
The solutions to the equation roots s^2-s+4 are s= 1/2+i(sqrt(15))/2 ,s= 1/2-i(sqrt(15))/2
Find the zeros of roots s^2-s+4
The zeros of roots s^2-s+4 are s= 1/2+i(sqrt(15))/2 ,s= 1/2-i(sqrt(15))/2