What are the solutions to the equation factor 6x^2-5x-4=0 ?

The solutions to the equation factor 6x^2-5x-4=0 are x=-1/2 ,x= 4/3

Find the zeros of factor 6x^2-5x-4=0

The zeros of factor 6x^2-5x-4=0 are x=-1/2 ,x= 4/3

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6 x^{2} - 5 x - 4 = 0

x = - \frac{1}{2}, x = \frac{4}{3}

Decimal Notation

x = - 0.5, x = 1.33333 \dots

Solution steps

6 x^{2} - 5 x - 4 = 0

Factor

6 x^{2} - 5 x - 4 : (2 x + 1) (3 x - 4)

(2 x + 1) (3 x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 1 = 0 or 3 x - 4 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

3 x - 4 = 0 : x = \frac{4}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = \frac{4}{3}

(2 x - 1) (x) = 120

x^{2} + 3 x + 13 = 3 - 4 x

10 b^{2} + 21 b + 6 = 2 b

x^{2} - 5 x + 2 = - 3 x + 10

(3 x - 7) (5 x - 12) = 0

What are the solutions to the equation factor 6x^2-5x-4=0 ?
The solutions to the equation factor 6x^2-5x-4=0 are x=-1/2 ,x= 4/3
Find the zeros of factor 6x^2-5x-4=0
The zeros of factor 6x^2-5x-4=0 are x=-1/2 ,x= 4/3