What are the solutions to the equation (2x-1)(x)=120 ?

The solutions to the equation (2x-1)(x)=120 are x=8,x=-15/2

Find the zeros of (2x-1)(x)=120

The zeros of (2x-1)(x)=120 are x=8,x=-15/2

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(2 x - 1) (x) = 120

x = 8, x = - \frac{15}{2}

Decimal Notation

x = 8, x = - 7.5

Solution steps

(2 x - 1) (x) = 120

Expand

(2 x - 1) (x) : 2 x^{2} - x

2 x^{2} - x = 120

Move

120

to the left side

2 x^{2} - x - 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 120 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 120) = 31

x_{1, 2} = \frac{- ( - 1 ) \pm 31}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 31}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 31}{2 \cdot 2}

x = \frac{- ( - 1 ) + 31}{2 \cdot 2} : 8

x = \frac{- ( - 1 ) - 31}{2 \cdot 2} : - \frac{15}{2}

The solutions to the quadratic equation are:

x = 8, x = - \frac{15}{2}

x^{2} + 3 x + 13 = 3 - 4 x

10 b^{2} + 21 b + 6 = 2 b

x^{2} - 5 x + 2 = - 3 x + 10

(3 x - 7) (5 x - 12) = 0

16 x^{2} = 81

What are the solutions to the equation (2x-1)(x)=120 ?
The solutions to the equation (2x-1)(x)=120 are x=8,x=-15/2
Find the zeros of (2x-1)(x)=120
The zeros of (2x-1)(x)=120 are x=8,x=-15/2