What are the solutions to the equation 5(x-5)^2-33=-28 ?

The solutions to the equation 5(x-5)^2-33=-28 are x=6,x=4

Find the zeros of 5(x-5)^2-33=-28

The zeros of 5(x-5)^2-33=-28 are x=6,x=4

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5 (x - 5)^{2} - 33 = - 28

x = 6, x = 4

Solution steps

5 (x - 5)^{2} - 33 = - 28

Move

33

to the right side

5 (x - 5)^{2} = 5

Divide both sides by

5

(x - 5)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = 1 : x = 6

Solve

x - 5 = - 1 : x = 4

The solutions to the quadratic equation are:

x = 6, x = 4

4 (x - 4)^{2} - 33 = - 5

2 v^{2} + 15 v + 19 = 0

0 = 2 x^{2} - 10 x + 7

- 18 x^{2} + 45 x - 25 = 0

a^{2} - 8 a + 12 = 2

What are the solutions to the equation 5(x-5)^2-33=-28 ?
The solutions to the equation 5(x-5)^2-33=-28 are x=6,x=4
Find the zeros of 5(x-5)^2-33=-28
The zeros of 5(x-5)^2-33=-28 are x=6,x=4