What are the solutions to the equation 0=2x^2-10x+7 ?

The solutions to the equation 0=2x^2-10x+7 are x=(5+sqrt(11))/2 ,x=(5-sqrt(11))/2

Find the zeros of 0=2x^2-10x+7

The zeros of 0=2x^2-10x+7 are x=(5+sqrt(11))/2 ,x=(5-sqrt(11))/2

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0 = 2 x^{2} - 10 x + 7

x = \frac{5 + 11}{2}, x = \frac{5 - 11}{2}

Decimal Notation

x = 4.15831 \dots, x = 0.84168 \dots

Solution steps

0 = 2 x^{2} - 10 x + 7

Switch sides

2 x^{2} - 10 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 2 \cdot 7}{2 \cdot 2}

(- 10)^{2} - 4 \cdot 2 \cdot 7 = 211

x_{1, 2} = \frac{- ( - 10 ) \pm 2 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 11}{2 \cdot 2}, x_{2} = \frac{- ( - 10 ) - 2 11}{2 \cdot 2}

x = \frac{- ( - 10 ) + 2 11}{2 \cdot 2} : \frac{5 + 11}{2}

x = \frac{- ( - 10 ) - 2 11}{2 \cdot 2} : \frac{5 - 11}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 11}{2}, x = \frac{5 - 11}{2}

- 18 x^{2} + 45 x - 25 = 0

a^{2} - 8 a + 12 = 2

- 3 (x + 2)^{2} = 24

150 x^{2} + x = 0

x^{2} + 2 x + 17 = 0

What are the solutions to the equation 0=2x^2-10x+7 ?
The solutions to the equation 0=2x^2-10x+7 are x=(5+sqrt(11))/2 ,x=(5-sqrt(11))/2
Find the zeros of 0=2x^2-10x+7
The zeros of 0=2x^2-10x+7 are x=(5+sqrt(11))/2 ,x=(5-sqrt(11))/2