What are the solutions to the equation 2v^2+15v+19=0 ?

The solutions to the equation 2v^2+15v+19=0 are v=(-15+sqrt(73))/4 ,v=(-15-sqrt(73))/4

Find the zeros of 2v^2+15v+19=0

The zeros of 2v^2+15v+19=0 are v=(-15+sqrt(73))/4 ,v=(-15-sqrt(73))/4

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2 v^{2} + 15 v + 19 = 0

v = \frac{- 15 + 73}{4}, v = \frac{- 15 - 73}{4}

Decimal Notation

v = - 1.61399 \dots, v = - 5.88600 \dots

Solution steps

2 v^{2} + 15 v + 19 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 2 \cdot 19}{2 \cdot 2}

1 5^{2} - 4 \cdot 2 \cdot 19 = 73

v_{1, 2} = \frac{- 15 \pm 73}{2 \cdot 2}

Separate the solutions

v_{1} = \frac{- 15 + 73}{2 \cdot 2}, v_{2} = \frac{- 15 - 73}{2 \cdot 2}

v = \frac{- 15 + 73}{2 \cdot 2} : \frac{- 15 + 73}{4}

v = \frac{- 15 - 73}{2 \cdot 2} : \frac{- 15 - 73}{4}

The solutions to the quadratic equation are:

v = \frac{- 15 + 73}{4}, v = \frac{- 15 - 73}{4}

0 = 2 x^{2} - 10 x + 7

- 18 x^{2} + 45 x - 25 = 0

a^{2} - 8 a + 12 = 2

- 3 (x + 2)^{2} = 24

150 x^{2} + x = 0

What are the solutions to the equation 2v^2+15v+19=0 ?
The solutions to the equation 2v^2+15v+19=0 are v=(-15+sqrt(73))/4 ,v=(-15-sqrt(73))/4
Find the zeros of 2v^2+15v+19=0
The zeros of 2v^2+15v+19=0 are v=(-15+sqrt(73))/4 ,v=(-15-sqrt(73))/4