What are the solutions to the equation -18x^2+45x-25=0 ?

The solutions to the equation -18x^2+45x-25=0 are x= 5/6 ,x= 5/3

Find the zeros of -18x^2+45x-25=0

The zeros of -18x^2+45x-25=0 are x= 5/6 ,x= 5/3

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- 18 x^{2} + 45 x - 25 = 0

x = \frac{5}{6}, x = \frac{5}{3}

Decimal Notation

x = 0.83333 \dots, x = 1.66666 \dots

Solution steps

- 18 x^{2} + 45 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 45 \pm 4 5 ^{2} - 4 ( - 18 ) ( - 25 )}{2 ( - 18 )}

4 5^{2} - 4 (- 18) (- 25) = 15

x_{1, 2} = \frac{- 45 \pm 15}{2 ( - 18 )}

Separate the solutions

x_{1} = \frac{- 45 + 15}{2 ( - 18 )}, x_{2} = \frac{- 45 - 15}{2 ( - 18 )}

x = \frac{- 45 + 15}{2 ( - 18 )} : \frac{5}{6}

x = \frac{- 45 - 15}{2 ( - 18 )} : \frac{5}{3}

The solutions to the quadratic equation are:

x = \frac{5}{6}, x = \frac{5}{3}

a^{2} - 8 a + 12 = 2

- 3 (x + 2)^{2} = 24

150 x^{2} + x = 0

x^{2} + 2 x + 17 = 0

4 x^{2} + 20 x = - 17

What are the solutions to the equation -18x^2+45x-25=0 ?
The solutions to the equation -18x^2+45x-25=0 are x= 5/6 ,x= 5/3
Find the zeros of -18x^2+45x-25=0
The zeros of -18x^2+45x-25=0 are x= 5/6 ,x= 5/3