What are the solutions to the equation 6u^2+5u=1 ?

The solutions to the equation 6u^2+5u=1 are u= 1/6 ,u=-1

Find the zeros of 6u^2+5u=1

The zeros of 6u^2+5u=1 are u= 1/6 ,u=-1

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6 u^{2} + 5 u = 1

u = \frac{1}{6}, u = - 1

Decimal Notation

u = 0.16666 \dots, u = - 1

Solution steps

6 u^{2} + 5 u = 1

Move

1

to the left side

6 u^{2} + 5 u - 1 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 6 ( - 1 )}{2 \cdot 6}

5^{2} - 4 \cdot 6 (- 1) = 7

u_{1, 2} = \frac{- 5 \pm 7}{2 \cdot 6}

Separate the solutions

u_{1} = \frac{- 5 + 7}{2 \cdot 6}, u_{2} = \frac{- 5 - 7}{2 \cdot 6}

u = \frac{- 5 + 7}{2 \cdot 6} : \frac{1}{6}

u = \frac{- 5 - 7}{2 \cdot 6} : - 1

The solutions to the quadratic equation are:

u = \frac{1}{6}, u = - 1

x^{2} + 2 x + 6

x, x^{2} + x y + y^{3} = 0

x^{2} - 8 x + 16

x^{2} + 8 x + 12 = 0

16 m^{2} + 72 m + 83 = 0

What are the solutions to the equation 6u^2+5u=1 ?
The solutions to the equation 6u^2+5u=1 are u= 1/6 ,u=-1
Find the zeros of 6u^2+5u=1
The zeros of 6u^2+5u=1 are u= 1/6 ,u=-1