What are the solutions to the equation 4b^2-8b-10=-5 ?

The solutions to the equation 4b^2-8b-10=-5 are b= 5/2 ,b=-1/2

Find the zeros of 4b^2-8b-10=-5

The zeros of 4b^2-8b-10=-5 are b= 5/2 ,b=-1/2

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4 b^{2} - 8 b - 10 = - 5

b = \frac{5}{2}, b = - \frac{1}{2}

Decimal Notation

b = 2.5, b = - 0.5

Solution steps

4 b^{2} - 8 b - 10 = - 5

Move

5

to the left side

4 b^{2} - 8 b - 5 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 ( - 5 )}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 (- 5) = 12

b_{1, 2} = \frac{- ( - 8 ) \pm 12}{2 \cdot 4}

Separate the solutions

b_{1} = \frac{- ( - 8 ) + 12}{2 \cdot 4}, b_{2} = \frac{- ( - 8 ) - 12}{2 \cdot 4}

b = \frac{- ( - 8 ) + 12}{2 \cdot 4} : \frac{5}{2}

b = \frac{- ( - 8 ) - 12}{2 \cdot 4} : - \frac{1}{2}

The solutions to the quadratic equation are:

b = \frac{5}{2}, b = - \frac{1}{2}

25 x^{2} - 8 x = 12 x - 4

3 x^{2} - 5 = 25

- 16 t^{2} - 20 t + 700 = 0

10 c^{2} + 9 c - 1 = 6 c^{2}

- 2 x^{2} + 16 x - 3 = 0

What are the solutions to the equation 4b^2-8b-10=-5 ?
The solutions to the equation 4b^2-8b-10=-5 are b= 5/2 ,b=-1/2
Find the zeros of 4b^2-8b-10=-5
The zeros of 4b^2-8b-10=-5 are b= 5/2 ,b=-1/2