What are the solutions to the equation 25x^2-8x=12x-4 ?

The solutions to the equation 25x^2-8x=12x-4 are x= 2/5

Find the zeros of 25x^2-8x=12x-4

The zeros of 25x^2-8x=12x-4 are x= 2/5

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25 x^{2} - 8 x = 12 x - 4

x = \frac{2}{5}

Decimal Notation

x = 0.4

Solution steps

25 x^{2} - 8 x = 12 x - 4

Move

4

to the left side

25 x^{2} - 8 x + 4 = 12 x

Move

12 x

to the left side

25 x^{2} - 20 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 25 \cdot 4}{2 \cdot 25}

(- 20)^{2} - 4 \cdot 25 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 25}

x = \frac{- ( - 20 )}{2 \cdot 25}

\frac{- ( - 20 )}{2 \cdot 25} = \frac{2}{5}

x = \frac{2}{5}

The solution to the quadratic equation is:

x = \frac{2}{5}

3 x^{2} - 5 = 25

- 16 t^{2} - 20 t + 700 = 0

10 c^{2} + 9 c - 1 = 6 c^{2}

- 2 x^{2} + 16 x - 3 = 0

3 x^{2} + 2 x - 1

What are the solutions to the equation 25x^2-8x=12x-4 ?
The solutions to the equation 25x^2-8x=12x-4 are x= 2/5
Find the zeros of 25x^2-8x=12x-4
The zeros of 25x^2-8x=12x-4 are x= 2/5