What are the solutions to the equation 3x^2-5=25 ?

The solutions to the equation 3x^2-5=25 are x=sqrt(10),x=-sqrt(10)

Find the zeros of 3x^2-5=25

The zeros of 3x^2-5=25 are x=sqrt(10),x=-sqrt(10)

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3 x^{2} - 5 = 25

x = 10, x = - 10

Decimal Notation

x = 3.16227 \dots, x = - 3.16227 \dots

Solution steps

3 x^{2} - 5 = 25

Move

5

to the right side

3 x^{2} = 30

Divide both sides by

3

x^{2} = 10

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 10, x = - 10

- 16 t^{2} - 20 t + 700 = 0

10 c^{2} + 9 c - 1 = 6 c^{2}

- 2 x^{2} + 16 x - 3 = 0

3 x^{2} + 2 x - 1

3 (x + 7)^{2} - 2 = 22

What are the solutions to the equation 3x^2-5=25 ?
The solutions to the equation 3x^2-5=25 are x=sqrt(10),x=-sqrt(10)
Find the zeros of 3x^2-5=25
The zeros of 3x^2-5=25 are x=sqrt(10),x=-sqrt(10)