What are the solutions to the equation 6v^2+18v=0 ?

The solutions to the equation 6v^2+18v=0 are v=0,v=-3

Find the zeros of 6v^2+18v=0

The zeros of 6v^2+18v=0 are v=0,v=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 v^{2} + 18 v = 0

v = 0, v = - 3

Solution steps

6 v^{2} + 18 v = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 6 \cdot 0}{2 \cdot 6}

1 8^{2} - 4 \cdot 6 \cdot 0 = 18

v_{1, 2} = \frac{- 18 \pm 18}{2 \cdot 6}

Separate the solutions

v_{1} = \frac{- 18 + 18}{2 \cdot 6}, v_{2} = \frac{- 18 - 18}{2 \cdot 6}

v = \frac{- 18 + 18}{2 \cdot 6} : 0

v = \frac{- 18 - 18}{2 \cdot 6} : - 3

The solutions to the quadratic equation are:

v = 0, v = - 3

6 n^{2} + 7 n - 11 = 5 n^{2}

s^{2} + 2 s + 8

5 x^{2} + 8 x + 2 x = - 11

3 v^{2} + 3 v - 4 = 0

(x + 3) (x - 5) = 9

What are the solutions to the equation 6v^2+18v=0 ?
The solutions to the equation 6v^2+18v=0 are v=0,v=-3
Find the zeros of 6v^2+18v=0
The zeros of 6v^2+18v=0 are v=0,v=-3