What are the solutions to the equation 6n^2+7n-11=5n^2 ?

The solutions to the equation 6n^2+7n-11=5n^2 are n=(-7+sqrt(93))/2 ,n=(-7-sqrt(93))/2

Find the zeros of 6n^2+7n-11=5n^2

The zeros of 6n^2+7n-11=5n^2 are n=(-7+sqrt(93))/2 ,n=(-7-sqrt(93))/2

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6 n^{2} + 7 n - 11 = 5 n^{2}

n = \frac{- 7 + 93}{2}, n = \frac{- 7 - 93}{2}

Decimal Notation

n = 1.32182 \dots, n = - 8.32182 \dots

Solution steps

6 n^{2} + 7 n - 11 = 5 n^{2}

Move

5 n^{2}

to the left side

n^{2} + 7 n - 11 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 11) = 93

n_{1, 2} = \frac{- 7 \pm 93}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 7 + 93}{2 \cdot 1}, n_{2} = \frac{- 7 - 93}{2 \cdot 1}

n = \frac{- 7 + 93}{2 \cdot 1} : \frac{- 7 + 93}{2}

n = \frac{- 7 - 93}{2 \cdot 1} : \frac{- 7 - 93}{2}

The solutions to the quadratic equation are:

n = \frac{- 7 + 93}{2}, n = \frac{- 7 - 93}{2}

s^{2} + 2 s + 8

5 x^{2} + 8 x + 2 x = - 11

3 v^{2} + 3 v - 4 = 0

(x + 3) (x - 5) = 9

9 x^{2} + 21 x - 8 = 0

What are the solutions to the equation 6n^2+7n-11=5n^2 ?
The solutions to the equation 6n^2+7n-11=5n^2 are n=(-7+sqrt(93))/2 ,n=(-7-sqrt(93))/2
Find the zeros of 6n^2+7n-11=5n^2
The zeros of 6n^2+7n-11=5n^2 are n=(-7+sqrt(93))/2 ,n=(-7-sqrt(93))/2