What are the solutions to the equation 3v^2+3v-4=0 ?

The solutions to the equation 3v^2+3v-4=0 are v=(-3+sqrt(57))/6 ,v=(-3-sqrt(57))/6

Find the zeros of 3v^2+3v-4=0

The zeros of 3v^2+3v-4=0 are v=(-3+sqrt(57))/6 ,v=(-3-sqrt(57))/6

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3 v^{2} + 3 v - 4 = 0

v = \frac{- 3 + 57}{6}, v = \frac{- 3 - 57}{6}

Decimal Notation

v = 0.75830 \dots, v = - 1.75830 \dots

Solution steps

3 v^{2} + 3 v - 4 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

3^{2} - 4 \cdot 3 (- 4) = 57

v_{1, 2} = \frac{- 3 \pm 57}{2 \cdot 3}

Separate the solutions

v_{1} = \frac{- 3 + 57}{2 \cdot 3}, v_{2} = \frac{- 3 - 57}{2 \cdot 3}

v = \frac{- 3 + 57}{2 \cdot 3} : \frac{- 3 + 57}{6}

v = \frac{- 3 - 57}{2 \cdot 3} : \frac{- 3 - 57}{6}

The solutions to the quadratic equation are:

v = \frac{- 3 + 57}{6}, v = \frac{- 3 - 57}{6}

(x + 3) (x - 5) = 9

9 x^{2} + 21 x - 8 = 0

(3 x - 2) x = (5 x - 1) x

2 (x + 1)^{2} + 30 = 32

33 b = 10 - 7 b^{2}

What are the solutions to the equation 3v^2+3v-4=0 ?
The solutions to the equation 3v^2+3v-4=0 are v=(-3+sqrt(57))/6 ,v=(-3-sqrt(57))/6
Find the zeros of 3v^2+3v-4=0
The zeros of 3v^2+3v-4=0 are v=(-3+sqrt(57))/6 ,v=(-3-sqrt(57))/6