What are the solutions to the equation roots s^2+2s+8 ?

The solutions to the equation roots s^2+2s+8 are s=-1+sqrt(7)i,s=-1-sqrt(7)i

Find the zeros of roots s^2+2s+8

The zeros of roots s^2+2s+8 are s=-1+sqrt(7)i,s=-1-sqrt(7)i

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roots

s^{2} + 2 s + 8

s = - 1 + 7 i, s = - 1 - 7 i

Solution steps

s^{2} + 2 s + 8

The roots are the intercepts with the x-axis

(y = 0)

s^{2} + 2 s + 8 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 8 : 27 i

s_{1, 2} = \frac{- 2 \pm 2 7 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 2 + 2 7 i}{2 \cdot 1}, s_{2} = \frac{- 2 - 2 7 i}{2 \cdot 1}

s = \frac{- 2 + 2 7 i}{2 \cdot 1} : - 1 + 7 i

s = \frac{- 2 - 2 7 i}{2 \cdot 1} : - 1 - 7 i

The solutions to the quadratic equation are:

s = - 1 + 7 i, s = - 1 - 7 i

5 x^{2} + 8 x + 2 x = - 11

3 v^{2} + 3 v - 4 = 0

(x + 3) (x - 5) = 9

9 x^{2} + 21 x - 8 = 0

(3 x - 2) x = (5 x - 1) x

What are the solutions to the equation roots s^2+2s+8 ?
The solutions to the equation roots s^2+2s+8 are s=-1+sqrt(7)i,s=-1-sqrt(7)i
Find the zeros of roots s^2+2s+8
The zeros of roots s^2+2s+8 are s=-1+sqrt(7)i,s=-1-sqrt(7)i