What are the solutions to the equation factor 9x^2+21x-8=0 ?

The solutions to the equation factor 9x^2+21x-8=0 are x= 1/3 ,x=-8/3

Find the zeros of factor 9x^2+21x-8=0

The zeros of factor 9x^2+21x-8=0 are x= 1/3 ,x=-8/3

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9 x^{2} + 21 x - 8 = 0

x = \frac{1}{3}, x = - \frac{8}{3}

Decimal Notation

x = 0.33333 \dots, x = - 2.66666 \dots

Solution steps

9 x^{2} + 21 x - 8 = 0

Factor

9 x^{2} + 21 x - 8 : (3 x - 1) (3 x + 8)

(3 x - 1) (3 x + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 1 = 0 or 3 x + 8 = 0

Solve

3 x - 1 = 0 : x = \frac{1}{3}

Solve

3 x + 8 = 0 : x = - \frac{8}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - \frac{8}{3}

(3 x - 2) x = (5 x - 1) x

2 (x + 1)^{2} + 30 = 32

33 b = 10 - 7 b^{2}

12 x^{2} - 288 x + 1260 = 0

v, \frac{m v ^{2}}{r} = q v B

What are the solutions to the equation factor 9x^2+21x-8=0 ?
The solutions to the equation factor 9x^2+21x-8=0 are x= 1/3 ,x=-8/3
Find the zeros of factor 9x^2+21x-8=0
The zeros of factor 9x^2+21x-8=0 are x= 1/3 ,x=-8/3