What are the solutions to the equation solvefor y,x^2+14xy+49y^2=100 ?

The solutions to the equation solvefor y,x^2+14xy+49y^2=100 are y=(-x+10)/7 ,y=-(x+10)/7

Find the zeros of solvefor y,x^2+14xy+49y^2=100

The zeros of solvefor y,x^2+14xy+49y^2=100 are y=(-x+10)/7 ,y=-(x+10)/7

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solve for

y, x^{2} + 14 x y + 49 y^{2} = 100

y = \frac{- x + 10}{7}, y = - \frac{x + 10}{7}

Solution steps

x^{2} + 14 x y + 49 y^{2} = 100

Move

100

to the left side

x^{2} + 14 x y + 49 y^{2} - 100 = 0

Write in the standard form

a x^{2} + b x + c = 0

49 y^{2} + 14 x y + x^{2} - 100 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 14 x \pm ( 14 x ) ^{2} - 4 \cdot 49 ( x ^{2} - 100 )}{2 \cdot 49}

(14 x)^{2} - 4 \cdot 49 (x^{2} - 100) = 140

y_{1, 2} = \frac{- 14 x \pm 140}{2 \cdot 49}

Separate the solutions

y_{1} = \frac{- 14 x + 140}{2 \cdot 49}, y_{2} = \frac{- 14 x - 140}{2 \cdot 49}

y = \frac{- 14 x + 140}{2 \cdot 49} : \frac{- x + 10}{7}

y = \frac{- 14 x - 140}{2 \cdot 49} : - \frac{x + 10}{7}

The solutions to the quadratic equation are:

y = \frac{- x + 10}{7}, y = - \frac{x + 10}{7}

4 x (2 x - 1) = 9 - 7 x

x^{2} + 2 x + 5 = 0

x^{2} - 12 x + c = 0

2 x^{2} - 5 x - 3

x^{2} + 2 x = 3

What are the solutions to the equation solvefor y,x^2+14xy+49y^2=100 ?
The solutions to the equation solvefor y,x^2+14xy+49y^2=100 are y=(-x+10)/7 ,y=-(x+10)/7
Find the zeros of solvefor y,x^2+14xy+49y^2=100
The zeros of solvefor y,x^2+14xy+49y^2=100 are y=(-x+10)/7 ,y=-(x+10)/7