What are the solutions to the equation 4x(2x-1)=9-7x ?

The solutions to the equation 4x(2x-1)=9-7x are x=(-3+3sqrt(33))/(16),x=(-3-3sqrt(33))/(16)

Find the zeros of 4x(2x-1)=9-7x

The zeros of 4x(2x-1)=9-7x are x=(-3+3sqrt(33))/(16),x=(-3-3sqrt(33))/(16)

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4 x (2 x - 1) = 9 - 7 x

x = \frac{- 3 + 3 33}{16}, x = \frac{- 3 - 3 33}{16}

Decimal Notation

x = 0.88960 \dots, x = - 1.26460 \dots

Solution steps

4 x (2 x - 1) = 9 - 7 x

Expand

4 x (2 x - 1) : 8 x^{2} - 4 x

8 x^{2} - 4 x = 9 - 7 x

Move

7 x

to the left side

8 x^{2} + 3 x = 9

Move

9

to the left side

8 x^{2} + 3 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 8 ( - 9 )}{2 \cdot 8}

3^{2} - 4 \cdot 8 (- 9) = 333

x_{1, 2} = \frac{- 3 \pm 3 33}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 3 + 3 33}{2 \cdot 8}, x_{2} = \frac{- 3 - 3 33}{2 \cdot 8}

x = \frac{- 3 + 3 33}{2 \cdot 8} : \frac{- 3 + 3 33}{16}

x = \frac{- 3 - 3 33}{2 \cdot 8} : \frac{- 3 - 3 33}{16}

The solutions to the quadratic equation are:

x = \frac{- 3 + 3 33}{16}, x = \frac{- 3 - 3 33}{16}

x^{2} + 2 x + 5 = 0

x^{2} - 12 x + c = 0

2 x^{2} - 5 x - 3

x^{2} + 2 x = 3

6 q^{2} + 10 q + 25 = 5 q^{2}

What are the solutions to the equation 4x(2x-1)=9-7x ?
The solutions to the equation 4x(2x-1)=9-7x are x=(-3+3sqrt(33))/(16),x=(-3-3sqrt(33))/(16)
Find the zeros of 4x(2x-1)=9-7x
The zeros of 4x(2x-1)=9-7x are x=(-3+3sqrt(33))/(16),x=(-3-3sqrt(33))/(16)