What are the solutions to the equation 5(5x-9)^2-39=41 ?

The solutions to the equation 5(5x-9)^2-39=41 are x= 13/5 ,x=1

Find the zeros of 5(5x-9)^2-39=41

The zeros of 5(5x-9)^2-39=41 are x= 13/5 ,x=1

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5 (5 x - 9)^{2} - 39 = 41

x = \frac{13}{5}, x = 1

Decimal Notation

x = 2.6, x = 1

Solution steps

5 (5 x - 9)^{2} - 39 = 41

Move

39

to the right side

5 (5 x - 9)^{2} = 80

Divide both sides by

5

(5 x - 9)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x - 9 = 16 : x = \frac{13}{5}

Solve

5 x - 9 = - 16 : x = 1

The solutions to the quadratic equation are:

x = \frac{13}{5}, x = 1

8 z^{2} + 13 z + 4 = 3 z^{2}

2 t^{2} - 3 t - 10 = 0

y, 9 y^{2} = x (x - 3)^{2}

s^{2} + 1

5 m^{2} + 8 m - 51 = 2 m^{2}

What are the solutions to the equation 5(5x-9)^2-39=41 ?
The solutions to the equation 5(5x-9)^2-39=41 are x= 13/5 ,x=1
Find the zeros of 5(5x-9)^2-39=41
The zeros of 5(5x-9)^2-39=41 are x= 13/5 ,x=1