What are the solutions to the equation v^2-7v+6=0 ?

The solutions to the equation v^2-7v+6=0 are v=6,v=1

Find the zeros of v^2-7v+6=0

The zeros of v^2-7v+6=0 are v=6,v=1

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v^{2} - 7 v + 6 = 0

v = 6, v = 1

Solution steps

v^{2} - 7 v + 6 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 6 = 5

v_{1, 2} = \frac{- ( - 7 ) \pm 5}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 7 ) + 5}{2 \cdot 1}, v_{2} = \frac{- ( - 7 ) - 5}{2 \cdot 1}

v = \frac{- ( - 7 ) + 5}{2 \cdot 1} : 6

v = \frac{- ( - 7 ) - 5}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

v = 6, v = 1

6 x + x^{2} + 9 = 0

- x^{2} + 5 x + 2

d^{2} + 9 d + 12 = - 4

y^{2} - 15 y - 54 = 0

(- 3) 1 0^{- 6} x^{2} + 0.003 x + 6 = 0

What are the solutions to the equation v^2-7v+6=0 ?
The solutions to the equation v^2-7v+6=0 are v=6,v=1
Find the zeros of v^2-7v+6=0
The zeros of v^2-7v+6=0 are v=6,v=1