What are the solutions to the equation 10x^2-4x+1=6x^2 ?

The solutions to the equation 10x^2-4x+1=6x^2 are x= 1/2

Find the zeros of 10x^2-4x+1=6x^2

The zeros of 10x^2-4x+1=6x^2 are x= 1/2

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10 x^{2} - 4 x + 1 = 6 x^{2}

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

10 x^{2} - 4 x + 1 = 6 x^{2}

Move

6 x^{2}

to the left side

4 x^{2} - 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 4 )}{2 \cdot 4}

\frac{- ( - 4 )}{2 \cdot 4} = \frac{1}{2}

x = \frac{1}{2}

The solution to the quadratic equation is:

x = \frac{1}{2}

16 x^{2} = 96 x - 150

8 z^{2} + 18 z - 7 = - 2

x^{2} + 2 x - 8 = 0

8 x^{2} - 8 = (3 x - 1)^{2}

r^{2} - 2 r + 2

What are the solutions to the equation 10x^2-4x+1=6x^2 ?
The solutions to the equation 10x^2-4x+1=6x^2 are x= 1/2
Find the zeros of 10x^2-4x+1=6x^2
The zeros of 10x^2-4x+1=6x^2 are x= 1/2