What are the solutions to the equation roots x^2+6x+18 ?

The solutions to the equation roots x^2+6x+18 are x=-3+3i,x=-3-3i

Find the zeros of roots x^2+6x+18

The zeros of roots x^2+6x+18 are x=-3+3i,x=-3-3i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

roots

x^{2} + 6 x + 18

x = - 3 + 3 i, x = - 3 - 3 i

Solution steps

x^{2} + 6 x + 18

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 6 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 18 : 6 i

x_{1, 2} = \frac{- 6 \pm 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 6 i}{2 \cdot 1}, x_{2} = \frac{- 6 - 6 i}{2 \cdot 1}

x = \frac{- 6 + 6 i}{2 \cdot 1} : - 3 + 3 i

x = \frac{- 6 - 6 i}{2 \cdot 1} : - 3 - 3 i

The solutions to the quadratic equation are:

x = - 3 + 3 i, x = - 3 - 3 i

- \frac{1}{3} x^{2} + \frac{2}{3} x + 5 = 0

x^{2} - 10 x + 89 = 0

8 w^{2} - 8 w + 2 = 0

y, x^{2} + x y + 2 y^{2} = 1

413 = 9 x^{2} + 2 x + 1

What are the solutions to the equation roots x^2+6x+18 ?
The solutions to the equation roots x^2+6x+18 are x=-3+3i,x=-3-3i
Find the zeros of roots x^2+6x+18
The zeros of roots x^2+6x+18 are x=-3+3i,x=-3-3i