What are the solutions to the equation solvefor x,y^3-2y=x^2 ?

The solutions to the equation solvefor x,y^3-2y=x^2 are x=sqrt(y^3-2y),x=-sqrt(y^3-2y)

Find the zeros of solvefor x,y^3-2y=x^2

The zeros of solvefor x,y^3-2y=x^2 are x=sqrt(y^3-2y),x=-sqrt(y^3-2y)

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solve for

x, y^{3} - 2 y = x^{2}

x = y^{3} - 2 y, x = - y^{3} - 2 y

Solution steps

y^{3} - 2 y = x^{2}

Switch sides

x^{2} = y^{3} - 2 y

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = y^{3} - 2 y, x = - y^{3} - 2 y

a^{2} = 33

4 + 9 x - 3 x^{2} = 2 - x

6 b^{2} - 7 b - 21 = - 1

5 (u + 6) (- u + 3) = 0

7 t^{2} - 18 t = 14 + 10 t

What are the solutions to the equation solvefor x,y^3-2y=x^2 ?
The solutions to the equation solvefor x,y^3-2y=x^2 are x=sqrt(y^3-2y),x=-sqrt(y^3-2y)
Find the zeros of solvefor x,y^3-2y=x^2
The zeros of solvefor x,y^3-2y=x^2 are x=sqrt(y^3-2y),x=-sqrt(y^3-2y)