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For the solutions are
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The solutions to the quadratic equation are:
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What are the solutions to the equation 3(2x-6)^2+6=27 ?
The solutions to the equation 3(2x-6)^2+6=27 are x=(sqrt(7)+6)/2 ,x=(-sqrt(7)+6)/2Find the zeros of 3(2x-6)^2+6=27
The zeros of 3(2x-6)^2+6=27 are x=(sqrt(7)+6)/2 ,x=(-sqrt(7)+6)/2