What are the solutions to the equation 3=6x^2+6x-9 ?

The solutions to the equation 3=6x^2+6x-9 are x=1,x=-2

Find the zeros of 3=6x^2+6x-9

The zeros of 3=6x^2+6x-9 are x=1,x=-2

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3 = 6 x^{2} + 6 x - 9

x = 1, x = - 2

Solution steps

3 = 6 x^{2} + 6 x - 9

Switch sides

6 x^{2} + 6 x - 9 = 3

Move

3

to the left side

6 x^{2} + 6 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 6 ( - 12 )}{2 \cdot 6}

6^{2} - 4 \cdot 6 (- 12) = 18

x_{1, 2} = \frac{- 6 \pm 18}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 6 + 18}{2 \cdot 6}, x_{2} = \frac{- 6 - 18}{2 \cdot 6}

x = \frac{- 6 + 18}{2 \cdot 6} : 1

x = \frac{- 6 - 18}{2 \cdot 6} : - 2

The solutions to the quadratic equation are:

x = 1, x = - 2

4 x^{2} - 3 x = - 3

3 x^{2} - 4 x - 4 = 3

9 r^{2} + 6 r + 4 = 0

16 (4 x - 5)^{2} = 9

(\frac{2}{5})^{2} + x^{2} = 1

What are the solutions to the equation 3=6x^2+6x-9 ?
The solutions to the equation 3=6x^2+6x-9 are x=1,x=-2
Find the zeros of 3=6x^2+6x-9
The zeros of 3=6x^2+6x-9 are x=1,x=-2