What are the solutions to the equation 2x(x-3)=x^2-9 ?

The solutions to the equation 2x(x-3)=x^2-9 are x=3

Find the zeros of 2x(x-3)=x^2-9

The zeros of 2x(x-3)=x^2-9 are x=3

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2 x (x - 3) = x^{2} - 9

x = 3

Solution steps

2 x (x - 3) = x^{2} - 9

Expand

2 x (x - 3) : 2 x^{2} - 6 x

2 x^{2} - 6 x = x^{2} - 9

Move

9

to the left side

2 x^{2} - 6 x + 9 = x^{2}

Move

x^{2}

to the left side

x^{2} - 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 6 )}{2 \cdot 1}

\frac{- ( - 6 )}{2 \cdot 1} = 3

x = 3

The solution to the quadratic equation is:

x = 3

- x^{2} + 6 x + 3 = x + 3

4 x^{2} + x + 12 = 0

5 x^{2} - 37 x - 24 = 0

8 x^{2} + 2 x - 1 = 0

5 (5 x - 6)^{2} - 27 = 18

What are the solutions to the equation 2x(x-3)=x^2-9 ?
The solutions to the equation 2x(x-3)=x^2-9 are x=3
Find the zeros of 2x(x-3)=x^2-9
The zeros of 2x(x-3)=x^2-9 are x=3