What are the solutions to the equation 5(2x-10)^2-23=32 ?

The solutions to the equation 5(2x-10)^2-23=32 are x=(sqrt(11)+10)/2 ,x=(-sqrt(11)+10)/2

Find the zeros of 5(2x-10)^2-23=32

The zeros of 5(2x-10)^2-23=32 are x=(sqrt(11)+10)/2 ,x=(-sqrt(11)+10)/2

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5 (2 x - 10)^{2} - 23 = 32

x = \frac{11 + 10}{2}, x = \frac{- 11 + 10}{2}

Decimal Notation

x = 6.65831 \dots, x = 3.34168 \dots

Solution steps

5 (2 x - 10)^{2} - 23 = 32

Move

23

to the right side

5 (2 x - 10)^{2} = 55

Divide both sides by

5

(2 x - 10)^{2} = 11

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 10 = 11 : x = \frac{11 + 10}{2}

Solve

2 x - 10 = - 11 : x = \frac{- 11 + 10}{2}

The solutions to the quadratic equation are:

x = \frac{11 + 10}{2}, x = \frac{- 11 + 10}{2}

- 5 x^{2} - 99 x - 480 = x

30 x^{2} + 40 = 0

4 x^{2} + 4 x = 1

120 = (2 x - 1) (x)

x^{2} - 6 = - 4 x - 6

What are the solutions to the equation 5(2x-10)^2-23=32 ?
The solutions to the equation 5(2x-10)^2-23=32 are x=(sqrt(11)+10)/2 ,x=(-sqrt(11)+10)/2
Find the zeros of 5(2x-10)^2-23=32
The zeros of 5(2x-10)^2-23=32 are x=(sqrt(11)+10)/2 ,x=(-sqrt(11)+10)/2