What are the solutions to the equation 5x^2+1=21 ?

The solutions to the equation 5x^2+1=21 are x=2,x=-2

Find the zeros of 5x^2+1=21

The zeros of 5x^2+1=21 are x=2,x=-2

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5 x^{2} + 1 = 21

x = 2, x = - 2

Solution steps

5 x^{2} + 1 = 21

Move

1

to the right side

5 x^{2} = 20

Divide both sides by

5

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

x^{2} - 8 x + 32 = 0

(5 - 1) x^{2} - 2 x - (5 + 1) = 0

x, h^{- 1} (x) = \frac{1}{2} x^{2}

5 a^{2} - 7 a - 10 = 0

2 x^{2} + 24 x + 32 = 0

What are the solutions to the equation 5x^2+1=21 ?
The solutions to the equation 5x^2+1=21 are x=2,x=-2
Find the zeros of 5x^2+1=21
The zeros of 5x^2+1=21 are x=2,x=-2