What are the solutions to the equation z^2+z=6 ?

The solutions to the equation z^2+z=6 are z=2,z=-3

Find the zeros of z^2+z=6

The zeros of z^2+z=6 are z=2,z=-3

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z^{2} + z = 6

z = 2, z = - 3

Solution steps

z^{2} + z = 6

Move

6

to the left side

z^{2} + z - 6 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 6) = 5

z_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 1 + 5}{2 \cdot 1}, z_{2} = \frac{- 1 - 5}{2 \cdot 1}

z = \frac{- 1 + 5}{2 \cdot 1} : 2

z = \frac{- 1 - 5}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

z = 2, z = - 3

x^{2} + x + \frac{1}{2}

x (4 x - 5) = 0

- 91.5 x^{2} - 18 x + 73.5 = 0

x^{2} - 16 x + 48 = 9

y, 9 x^{2} - 4 y^{2} - 36 x - 16 y + 20 = 0

What are the solutions to the equation z^2+z=6 ?
The solutions to the equation z^2+z=6 are z=2,z=-3
Find the zeros of z^2+z=6
The zeros of z^2+z=6 are z=2,z=-3